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7n^2-22n-24=0
a = 7; b = -22; c = -24;
Δ = b2-4ac
Δ = -222-4·7·(-24)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-34}{2*7}=\frac{-12}{14} =-6/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+34}{2*7}=\frac{56}{14} =4 $
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